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8n^2+2n-91=0
a = 8; b = 2; c = -91;
Δ = b2-4ac
Δ = 22-4·8·(-91)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-54}{2*8}=\frac{-56}{16} =-3+1/2 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+54}{2*8}=\frac{52}{16} =3+1/4 $
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